Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.1 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 428: 107

Answer

Makes sense.

Work Step by Step

For $20x^{3}+8x^{2}$, the gcf is $4x^{2}$, and we factor $20x^{3}$as $4x^{2}\cdot 5x.$ For $20x^{3}+10x$, the gcf is $10x$, and we factor $20x^{3}$as $10x\cdot 2x^{2}.$ Makes sense.
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