## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$(p^2-q^2)(p^4+p^2q^2+q^4)$
Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of 2 cubes, the factored form of the given expression, $p^6-q^6 ,$ is \begin{array}{l} (p^2-q^2)[ (p^2)^2-(p^2)(-q^2)+(-q^2)^2] \\\\= (p^2-q^2)(p^4+p^2q^2+q^4) .\end{array}