Answer
$(x-0.1)(x^2+0.1x+0.01)$
Work Step by Step
Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of 2 cubes, the factored form of the given expression, $
x^3-0.001
,$ is
\begin{array}{l}
(x-0.1)[ (x)^2-(x)(-0.1)+(-0.1)^2]
\\\\=
(x-0.1)(x^2+0.1x+0.01)
.\end{array}