Answer
$2(y-4)(y^2+4y+16)$
Work Step by Step
Factoring the $GCF=
2
,$ the given expression, $
2y^3-128
,$ is equivalent to
\begin{array}{l}
2(y^3-64)
.\end{array}
Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of 2 cubes, the factored form of the expression, $
2(y^3-64)
,$ is
\begin{array}{l}
2(y-4)[ (y)^2-(y)(-4)+(-4)^2]
\\\\=
2(y-4)(y^2+4y+16)
.\end{array}