Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$(t-3)(t^2+3t+9)$
Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of 2 cubes, the factored form of the given expression, $t^3-27 ,$ is \begin{array}{l} (t-3)[(t)^2-(t)(-3)+(-3)^2] \\\\= (t-3)[t^2+3t+9] \\\\= (t-3)(t^2+3t+9) .\end{array}