## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$(y-0.5)(y^2+0.5y+0.25)$
Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of 2 cubes, the factored form of the given expression, $y^3-0.125 ,$ is \begin{array}{l} (y-0.5)[ (y)^2-(y)(-0.5)+(-0.5)^2] \\\\= (y-0.5)(y^2+0.5y+0.25) .\end{array}