## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$(t^2+4y^2)(t^4-4t^2y^2+16y^4)$
Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of 2 cubes, the factored form of the given expression, $t^6+64y^6 ,$ is \begin{array}{l} (t^2+4y^2)[ (t^2)^2-(t^2)(4y^2)+(4y^2)^2] \\\\= (t^2+4y^2)(t^4-4t^2y^2+16y^4) .\end{array}