Chapter 5 - Polynomials and Factoring - 5.5 Factoring Sums or Differences of Cubes - 5.5 Exercise Set - Page 338: 22

$(y-z)(y^2+yz+z^2)$

Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of 2 cubes, the factored form of the given expression, $ y^3-z^3 ,$ is \begin{array}{l} (y-z)[(y)^2-(y)(-z)+(-z)^2] \\\\= (y-z)(y^2+yz+z^2) .\end{array}