## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$(3x+1)(9x^2-3x+1)$
Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of 2 cubes, the factored form of the given expression, $27x^3+1 ,$ is \begin{array}{l} (3x+1)[(3x)^2-(3x)(1)+(1)^2] \\\\= (3x+1)(9x^2-3x+1) .\end{array}