## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$8(2x^2-t^2)(4x^4-2t^2x^2+t^4)$
Factoring the $GCF= 8 ,$ the given expression, $64x^6-8t^6 ,$ is equivalent to \begin{array}{l} 8(8x^6-t^6) .\end{array} Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of 2 cubes, the factored form of the expression, $8(8x^6-t^6) ,$ is \begin{array}{l} 8(2x^2-t^2)[ (2x^2)^2-(2x^2)(t^2)+(t^2)^2] \\\\= 8(2x^2-t^2)(4x^4-2t^2x^2+t^4) .\end{array}