Answer
$8(2x^2-t^2)(4x^4-2t^2x^2+t^4)$
Work Step by Step
Factoring the $GCF=
8
,$ the given expression, $
64x^6-8t^6
,$ is equivalent to
\begin{array}{l}
8(8x^6-t^6)
.\end{array}
Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of 2 cubes, the factored form of the expression, $
8(8x^6-t^6)
,$ is
\begin{array}{l}
8(2x^2-t^2)[ (2x^2)^2-(2x^2)(t^2)+(t^2)^2]
\\\\=
8(2x^2-t^2)(4x^4-2t^2x^2+t^4)
.\end{array}