Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.5 Factoring Sums or Differences of Cubes - 5.5 Exercise Set - Page 338: 37



Work Step by Step

Factoring the $GCF= 8 ,$ the given expression, $ 64x^6-8t^6 ,$ is equivalent to \begin{array}{l} 8(8x^6-t^6) .\end{array} Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of 2 cubes, the factored form of the expression, $ 8(8x^6-t^6) ,$ is \begin{array}{l} 8(2x^2-t^2)[ (2x^2)^2-(2x^2)(t^2)+(t^2)^2] \\\\= 8(2x^2-t^2)(4x^4-2t^2x^2+t^4) .\end{array}
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