## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$(t^2+1)(t^4-t^2+1)$
Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of 2 cubes, the factored form of the given expression, $t^6+1 ,$ is \begin{array}{l} (t^2+1)[ (t^2)^2-(t^2)(1)+(1)^2] \\\\= (t^2+1)(t^4-t^2+1) .\end{array}