## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$(z+1)(z^2-z+1)$
Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of 2 cubes, the factored form of the given expression, $z^3+1 ,$ is \begin{array}{l} (z+1)[(z)^2-(z)(1)+(1)^2] \\\\= (z+1)(z^2-z+1) .\end{array}