## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$(2a+1)(4a^2-2a+1)$
Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of 2 cubes, the factored form of the given expression, $8a^3+1 ,$ is \begin{array}{l} (2a+1)[(2a)^2-(2a)(1)+(1)^2] \\\\= (2a+1)(4a^2-2a+1) .\end{array}