## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$(3-2t)(9+6t+4t^2)$
Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of 2 cubes, the factored form of the given expression, $27-8t^3 ,$ is \begin{array}{l} (3-2t)[(3)^2-(3)(-2t)+(-2t)^2] \\\\= (3-2t)(9+6t+4t^2) .\end{array}