## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$(x-y)(x^2+xy+y^2)$
Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of 2 cubes, the factored form of the given expression, $x^3-y^3 ,$ is \begin{array}{l} (x-y)[(x)^2-(x)(-y)+(-y)^2] \\\\= (x-y)(x^2+xy+y^2) .\end{array}