## College Algebra (6th Edition)

Published by Pearson

# Chapter 2 - Functions and Graphs - Exercise Set 2.8 - Page 319: 7

#### Answer

$d=\sqrt{29}\approx5.39$

#### Work Step by Step

$(-2,-6)$ and $(3,-4)$ The distance between two points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is $d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ Substitute the given points into the formula and evaluate: $d=\sqrt{[3-(-2)]^{2}+[-4-(-6)]^{2}}=...$ $...=\sqrt{(3+2)^{2}+(-4+6)^{2}}=\sqrt{5^{2}+2^{2}}=...$ $...=\sqrt{25+4}=\sqrt{29}\approx5.39$

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