## College Algebra (6th Edition)

$d=\sqrt{29}\approx5.39$
$(-2,-6)$ and $(3,-4)$ The distance between two points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is $d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ Substitute the given points into the formula and evaluate: $d=\sqrt{[3-(-2)]^{2}+[-4-(-6)]^{2}}=...$ $...=\sqrt{(3+2)^{2}+(-4+6)^{2}}=\sqrt{5^{2}+2^{2}}=...$ $...=\sqrt{25+4}=\sqrt{29}\approx5.39$