## College Algebra (6th Edition)

Center: $(-3,2)$ $;$ Radius: $2$ Domain: $[-5,-1]$ $;$ Range: $[0,4]$ The graph is:
$(x+3)^{2}+(y-2)^{2}=4$ The standard form of the equation of a circle is $(x-h)^{2}+(y-k)^{2}=r^{2}$, where $(h,k)$ is the center of the circle and $r$ is its radius. From the equation given, it can be seen that $(h,k)=(-3,2)$ and that $r^{2}=4$ The center of the circle is $(-3,2)$ The radius of the circle is: $r^{2}=4$ $\sqrt{r^{2}}=\sqrt{4}$ $r=2$ From the equation's graph (shown below), it can be seen that its domain is $[-5,-1]$ and its range is $[0,4]$