College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.8 - Page 319: 42

Answer

Center: $(0,0)$ $;$ Radius: $7$ Domain: $[-7,7]$ $;$ Range: $[-7,7]$ The graph is:

Work Step by Step

$x^{2}+y^{2}=49$ The standard form of the equation of a circle is $(x-h)^{2}+(y-k)^{2}=r^{2}$, where $(h,k)$ is the center of the circle and $r$ is its radius. From the equation given, it can be seen that $(h,k)= (0,0)$ and that $r^{2}=49$ The center of the circle is the origin. The radius of the circle is: $r^{2}=49$ $\sqrt{r^{2}}=\sqrt{49}$ $r=7$ From the equation's graph (shown below), it can be seen that its domain is $[-7,7]$ and its range is $[-7,7]$
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