College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.8 - Page 319: 17

Answer

$d = 2.24$

Work Step by Step

$d = \sqrt {(\frac{7}{3}-\frac{1}{3})^{2} + (\frac{1}{5} - \frac{6}{5})^{2}}$ $= \sqrt {(2)^{2} + (-1)^{2}}$ $= \sqrt {4 + 1}$ $= \sqrt {5}$ $= 2.23606...$ $= 2.24$
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