College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.8 - Page 319: 16

Answer

$d = 11.09$

Work Step by Step

$d = \sqrt {(2\sqrt {3} - (-\sqrt {3}))^{2}+(\sqrt {6} -5\sqrt {6})^2}$ $=\sqrt {(2\sqrt {3} +\sqrt {3}))^{2}+(-4\sqrt {6})^2}$ $= \sqrt {(3\sqrt {3} )^{2}+(-4\sqrt {6})^2}$ $= \sqrt {(9 \times 3) + (16 \times 6)}$ $= \sqrt {27 + 96}$ $= \sqrt {123}$ $= 11.0905...$ $= 11.09$
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