College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.8 - Page 319: 27

Answer

Midpoint $=(1,5\sqrt{5})$

Work Step by Step

$(8,3\sqrt{5})$ and $(-6,7\sqrt{5})$ The midpoint of a segment with endpoints $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is $\Big(\dfrac{x_{1}+x_{2}}{2},\dfrac{y_{1}+y_{2}}{2}\Big)$ Substitute the given points into the formula and evaluate: Midpoint $=\Big(\dfrac{8-6}{2},\dfrac{3\sqrt{5}+7\sqrt{5}}{2}\Big)=\Big(\dfrac{2}{2},\dfrac{10\sqrt{5}}{2}\Big)=...$ $...=(1,5\sqrt{5})$
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