Answer
Center: $(-4,-5)$ $;$ Radius: $6$
Domain: $[-10,2]$ $;$ Range: $[-11,1]$
The graph is:
Work Step by Step
$(x+4)^{2}+(y+5)^{2}=36$
The standard form of the equation of a circle is $(x-h)^{2}+(y-k)^{2}=r^{2}$, where $(h,k)$ is the center of the circle and $r$ is its radius.
From the equation given, it can be seen that $(h,k)=(-4,-5)$ and that $r^{2}=36$
The center of the circle is $(-4,-5)$
The radius of the circle is:
$r^{2}=36$
$\sqrt{r^{2}}=\sqrt{36}$
$r=6$
From the equation's graph (shown below), it can be seen that its domain is $[-10,2]$ and its range is $[-11,1]$