Answer
Center: $(3,1)$ $;$ Radius: $6$
Domain: $[-3,9]$ $;$ Range: $[-5,7]$
The graph is:
Work Step by Step
$(x-3)^{2}+(y-1)^{2}=36$
The standard form of the equation of a circle is $(x-h)^{2}+(y-k)^{2}=r^{2}$, where $(h,k)$ is the center of the circle and $r$ is its radius.
From the equation given, it can be seen that $(h,k)=(3,1)$ and that $r^{2}=36$
The center of the circle is $(3,1)$
The radius of the circle is:
$r^{2}=36$
$\sqrt{r^{2}}=\sqrt{36}$
$r=6$
From the equation's graph (shown below), it can be seen that its domain is $[-3,9]$ and its range is $[-5,7]$