College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.8 - Page 319: 28

Answer

Midpoint $=(5\sqrt{3},-4)$

Work Step by Step

$(7\sqrt{3},-6)$ and $(3\sqrt{3},-2)$ The midpoint of a segment with endpoints $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is $\Big(\dfrac{x_{1}+x_{2}}{2},\dfrac{y_{1}+y_{2}}{2}\Big)$ Substitute the given points into the formula and evaluate: Midpoint $=\Big(\dfrac{7\sqrt{3}+3\sqrt{3}}{2},\dfrac{-6-2}{2}\Big)=\Big(\dfrac{10\sqrt{3}}{2},\dfrac{-8}{2}\Big)=...$ $...=(5\sqrt{3},-4)$
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