College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.8 - Page 319: 46

Answer

Center: $(-1,4)$ $;$ Radius: $5$ Domain: $[-6,4]$ $;$ Range: $[-1,9]$ The graph is:

Work Step by Step

$(x+1)^{2}+(y-4)^{2}=25$ The standard form of the equation of a circle is $(x-h)^{2}+(y-k)^{2}=r^{2}$, where $(h,k)$ is the center of the circle and $r$ is its radius. From the equation given, it can be seen that $(h,k)=(-1,4)$ and that $r^{2}=25$ The center of the circle is $(-1,4)$ The radius of the circle is: $r^{2}=25$ $\sqrt{r^{2}}=\sqrt{25}$ $r=5$ From the equation's graph (shown below), it can be seen that its domain is $[-6,4]$ and its range is $[-1,9]$
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