# Chapter 2 - Functions and Graphs - Exercise Set 2.8 - Page 319: 39

$(x+4)^{2}+y^{2}=100$

#### Work Step by Step

We know that the standard form of the equation of a circle with center $(h,k)$ and radius $r$ is $(x-h)^{2}+(y-k)^{2}=r^{2}$. Therefore, we can plug in the given values for $h$, $k$, and $r$ and simplify. $(x-(-4))^{2}+(y-0)^{2}=(10)^{2}$ $(x+4)^{2}+y^{2}=100$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.