Answer
Center: $(-2,0)$ $;$ Radius: $4$
Domain: $[-6,2]$ $;$ Range: $[-4,4]$
The graph is:
Work Step by Step
$(x+2)^{2}+y^{2}=16$
The standard form of the equation of a circle is $(x-h)^{2}+(y-k)^{2}=r^{2}$, where $(h,k)$ is the center of the circle and $r$ is its radius.
From the equation given, it can be seen that $(h,k)=(-2,0)$ and that $r^{2}=16$
The center of the circle is $(-2,0)$
The radius of the circle is:
$r^{2}=16$
$\sqrt{r^{2}}=\sqrt{16}$
$r=4$
From the equation's graph (shown below), it can be seen that its domain is $[-6,2]$ and its range is $[-4,4]$
