College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.8 - Page 319: 18

Answer

$d = 1.41$

Work Step by Step

$d = \sqrt {((-\frac{1}{4})-(\frac{3}{4}))^{2}+ ((-\frac{1}{7})-(\frac{6}{7}))^{2}}$ $ = \sqrt {(-\frac{1}{4}-\frac{3}{4}))^{2}+ (-\frac{1}{7}-\frac{6}{7}))^{2}}$ $= \sqrt {(-1)^{2} + (-1)^{2}}$ $= \sqrt {1 + 1}$ $=\sqrt {2}$ $= 1.41421...$ $= 1.41$
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