Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 608: 78b

Answer

$\frac{dQ_L}{dt} = 4.16 \times 10^3 W$

Work Step by Step

The rate of exhaust heat output can be found using this equation $\frac{dQ_L}{dt} = \frac{dQ_H}{dt} - \frac{dW}{dt}$ From (a), $\frac{dQ_H}{dt} = 4664.2 W$ and the power $\frac{dW}{dt} = 500W$ $\frac{dQ_L}{dt} = 4664.2 W - 500W$ $\frac{dQ_L}{dt} = 4164.2 W = 4.16 \times 10^3 W$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.