Answer
$\Delta S=0.650\frac{J}{K}$
Work Step by Step
We know that:
$\Delta S=Q(\frac{1}{T_2}-\frac{1}{T_1})$
We plug in the known values to obtain:
$\Delta S=260(\frac{1}{200}-\frac{1}{400})=0.650\frac{J}{K}$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 608: 67b
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