Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 608: 66b

$Q_{in} = 710J$

The kitchen acts as a reservoir here. Thus, we need to find the $Q_{in}$ into the reservoir. The heat that is exhausted to the kitchen can be calculated as the following equation $Q_{in} = Q_{out} + W $ Where $Q_{out} = 560 J$ where energy that is exhausted by the refrigerator to the kitchen. and $W = 150J$ $Q_{in} = 560 J + 150J $ $Q_{in} = 710J$