Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 608: 62a

Answer

$Q = 700J$

Work Step by Step

From the T-S diagram, the area under the graph indicates the energy transfer as heat, $Q = \int T dS$. The heat transfer in process $1 \rightarrow 2$ is the area of rectangle, $Q = (350K)(8J/K - 6 J/K) $ $Q = (350K)(2.0J/K)$ $Q = 700J$
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