Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 608: 66a

Answer

$K = 3.73 $

Work Step by Step

The coefficient of performance (COP) equation for refrigerator is $K = \frac{Q_H}{W}, $ where $Q_H $ is the heat leaving the system and $W$ is the energy required for work done. Taking values from the question, $K = \frac{560J}{150J} $ $K = 3.73 $
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