Answer
$Q=Q_{int}+Q_{out}=200J-125J=75J$
Work Step by Step
We know that:
$Q=T\Delta S$
Next, we find $Q_{int}$ and $Q_{out}$:
$Q_{int}=400(0.60-0.10)=200J$
$Q_{out}=250(0.10-0.60)=-125J$
Now;
$Q=Q_{int}+Q_{out}=200J-125J=75J$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 608: 76a
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