Answer
$T_f = 229K$
Work Step by Step
From equation $Q = mc(T_f - T_i)$
In equilibrium state, final temperature, $T_f$ is the same in both blocks. We take $m_1 = Tungstent$ and $m_2 = Silver$ So
$m_{1}c_{1}(T_f - T_{i(1)}) =m_{2}c_{2}(T_f - T_{i(2)}) $
Here we solve for $T_f$
$T_f = \frac{m_{1}c_{1}T_{i(1)} + m_{2}c_{2} T_{i(2)}}{m_{1}c_{1} + m_{2}c_{2}} $
$T_f = \frac{(0.045 kg) (133 J/kg.K)(303K) + (0.025 kg) (233J/kg.K) (153K)}{(0.045 kg) (133 J/kg.K) + (0.025 kg) (233/kg.K)} $
$T_f = 229K$
