Answer
$\Delta S_{tungsten} = -1.689 J/K$
Work Step by Step
The equation to find the entropy for tungsten is
$\Delta S_{tungsten} = mc \space ln \frac{T_f}{T_i}$
Taking $T_f = 229K$ from (a)
$\Delta S_{tungsten} = (0.045 kg)(134 J/kg.K) ln \frac{229K}{303K} $
$\Delta S_{tungsten} = -1.689 J/K$
