Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 608: 77

Answer

$\epsilon = \frac{1}{K + 1 }$

Work Step by Step

We know the efficiency of an ideal heat engine equation is $\epsilon = \frac{|W|}{|Q_H|} $ And the equation of coefficient of performance (COP) in a reversible refrigerator is $K = \frac{|Q_H| - |W|}{|W|} $ $K = \frac{|Q_H| }{|W|} - \frac{|W|}{|W|} $ $K = \frac{|Q_H| }{|W|} - 1$ , but $\frac{|W|}{|Q_H|} = \epsilon $. substitute $\epsilon$ into the $K$ equation $K = \frac{1}{\epsilon} - 1$ , rearrange the equation $\frac{1}{\epsilon} = K + 1 $ $\epsilon = \frac{1}{K + 1 }$
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