Answer
$\Delta S = 4.45 J/K$
Work Step by Step
The entropy change for each reservoir is
$\Delta S = \frac{+|Q|}{T_L} + \frac{-|Q|}{T_H}$
$\Delta S = \frac{+|5030J|}{273 + 24} + \frac{-|5030J|}{273 + 130 }$
$\Delta S = \frac{+|5030J|}{297} + \frac{-|5030J|}{403 + 130 }$
$\Delta S = 4.45 J/K$
