Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 608: 72

Answer

$\epsilon=25\%$

Work Step by Step

We know that: $W=(\frac{750\frac{MJ}{s}}{3600s})=2.7\times 10^6MJ$ Now the efficiency of fossil-fuel power can be calculated as $\epsilon=\frac{2.7\times 10^6MJ}{10.6\times 10^6MJ}=0.253=25\%$
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