Answer
$\epsilon=25\%$
Work Step by Step
We know that:
$W=(\frac{750\frac{MJ}{s}}{3600s})=2.7\times 10^6MJ$
Now the efficiency of fossil-fuel power can be calculated as
$\epsilon=\frac{2.7\times 10^6MJ}{10.6\times 10^6MJ}=0.253=25\%$
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