Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 608: 64b

Answer

$|W|=231J$

Work Step by Step

We know that: $|W|=\frac{Q_L}{\frac{T_L}{T_H-T_L}}$ We plug in the known values to obtain: $|W|=\frac{1000}{\frac{260}{320-260}}=231J$
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