Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 2 - Motion Along a Straight Line - Problems - Page 33: 22l



Work Step by Step

We first differentiate $v=\frac{dx}{dt}=6t-6t^2$ to find the expression for $a$: Therefore, $a=\frac{dv}{dt}=6-12t$ Now, we substitute $t=3$ in the expression to find the value of $a$ at $t=3s$: $a_{(3)}=6-12(3)=6-36=-30\frac{m}{s^2}$
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