# Chapter 2 - Motion Along a Straight Line - Problems - Page 33: 22i

$v_{(4)}=-72\frac{m}{s}$

#### Work Step by Step

We need to differentiate $x=3t^2-2t^3$ to find $v$: Therefore, $v=\frac{dx}{dt}=6t-6t^2$ For $t=4s$ $v_{(4)}=6(4)-6(4)^2=24-96=-72\frac{m}{s}$

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