## Fundamentals of Physics Extended (10th Edition)

$4.0$ m
In part (a), we found that: $v(t)=\displaystyle \frac{d}{dt}x(t)=12t$ This means that when $t=0$ s$, v(0)=0$ m/s. The position at t=0 is found by inserting t=0 into $x(t)$: $x(0)=4.0-6.0(0)=4.0$ m