## Fundamentals of Physics Extended (10th Edition)

$v_{(2)}=-12\frac{m}{s}$
We need to differentiate $x=3t^2-2t^3$ to find $v$. Therefore, $v=\frac{dx}{dt}=6t-6t^2$ For $t=2s$, $v_{(2)}=6(2)-6(2)^2=-12\frac{m}{s}$