Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 2 - Motion Along a Straight Line - Problems: 22f

Answer

$v=0\frac{m}{s}$

Work Step by Step

As $x=3t^2-2t^3$, we differentiate it to find $v$. Therefore, $v=\frac{dx}{dt}=6t-6t^2$ For $t=1s$, $v=6(1)-6(1)^2=0\frac{m}{s}$
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