Answer
$v=0\frac{m}{s}$
Work Step by Step
As $x=3t^2-2t^3$, we differentiate it to find $v$.
Therefore, $v=\frac{dx}{dt}=6t-6t^2$
For $t=1s$,
$v=6(1)-6(1)^2=0\frac{m}{s}$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 2 - Motion Along a Straight Line - Problems - Page 33: 22f
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