## Fundamentals of Physics Extended (10th Edition)

$v=0\frac{m}{s}$
As $x=3t^2-2t^3$, we differentiate it to find $v$. Therefore, $v=\frac{dx}{dt}=6t-6t^2$ For $t=1s$, $v=6(1)-6(1)^2=0\frac{m}{s}$