Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 2 - Motion Along a Straight Line - Problems: 18h

Answer

$a=-24\frac{m}{s^2}$

Work Step by Step

We have to find acceleration when $v=0$ (not including when $t=0$). From part(e), we have $t=4s$ Acceleration is given as: $a=24-12t$ We plug in the value $t=4$ to obtain: $a=24-12(4)$ $a=-24\frac{m}{s^2}$
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