## Fundamentals of Physics Extended (10th Edition)

$a_{(2)}=-18\frac{m}{s^2}$
We differentiate $v=\frac{dx}{dt}=6t-6t^2$ to find the expression for $a$: Therefore, $a=\frac{dv}{dt}=6-12t$ For $t=2s$ $a_{(2)}=6-12(2)=6-24=-18\frac{m}{s^2}$