# Chapter 2 - Motion Along a Straight Line - Problems: 22k

$a_{(2)}=-18\frac{m}{s^2}$

#### Work Step by Step

We differentiate $v=\frac{dx}{dt}=6t-6t^2$ to find the expression for $a$: Therefore, $a=\frac{dv}{dt}=6-12t$ For $t=2s$ $a_{(2)}=6-12(2)=6-24=-18\frac{m}{s^2}$

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