Answer
$a_{(2)}=-18\frac{m}{s^2}$
Work Step by Step
We differentiate $v=\frac{dx}{dt}=6t-6t^2$ to find the expression for $a$:
Therefore, $a=\frac{dv}{dt}=6-12t$
For $t=2s$
$a_{(2)}=6-12(2)=6-24=-18\frac{m}{s^2}$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 2 - Motion Along a Straight Line - Problems - Page 33: 22k
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