## Fundamentals of Physics Extended (10th Edition)

Published by Wiley

# Chapter 2 - Motion Along a Straight Line - Problems - Page 33: 18e

#### Answer

$t=4s$

#### Work Step by Step

When the velocity is zero then the maximum positive coordinate reached by particle occurs: $v=24t-6t^2=0$ Taking $t$ common we obtain: $t(24-6t)=0$ Thus, either $t=0 s$ or $24-6t=0$, which simplifies to $t=4s$ So, the particle reaches the maximum position at time $t=4s$

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