## Fundamentals of Physics Extended (10th Edition)

$t=4s$
When the velocity is zero then the maximum positive coordinate reached by particle occurs: $v=24t-6t^2=0$ Taking $t$ common we obtain: $t(24-6t)=0$ Thus, either $t=0 s$ or $24-6t=0$, which simplifies to $t=4s$ So, the particle reaches the maximum position at time $t=4s$