Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 2 - Motion Along a Straight Line - Problems: 21c

Answer

$v_{avg}=1.47m/s$

Work Step by Step

Average velocity is defined as $$v_{avg}=\frac{\Delta x}{\Delta t}$$ The man stands still for five minutes, so his displacement is zero for that period. He walks at 2.20m/s for four minutes (from 5-9min.), which is 4(60s)=240 seconds. Solving the formula for displacement yields $$\Delta x = v\Delta t$$ Substituting known values of $v=2.20m/s$ and $\Delta t=240s$ yields $$\Delta x = (2.20m/s)(240s)=528m$$ Substituting this displacement $\Delta x=528m$ and $\Delta t=6.00min=6(60s)=360s$ (total time traveled) yields an average velocity of $$v_{avg}=\frac{528m}{360s}=1.47m/s$$
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