## Fundamentals of Physics Extended (10th Edition)

$a_{(1)}=-6\frac{m}{s^2}$
We need to differentiate $v=\frac{dx}{dt}=6t-6t^2$ to find the expression for $a$: $a=\frac{dv}{dt}=6-12t$ Next, we substitute $t=1$ in the expression of $a$ to find the value of $a$ at $t=1s$: $a_{(1)}=6-12(1)=-6\frac{m}{s^2}$